Answer:
Okey then bye
sayonara
I have to sleep
According to the Question
It is given that
We have to calculate the distance covered by body.
we will use here kinematics equation of motion.
Where v is the final velocity
a is the acceleration
u is the initial velocity
v is the final velocity
s is the displacement of the body
Substitute the value we get
=> 98² = 65²+ 2*2.75*s
=> 98² - 65² = 2*2.75*s
=> (98-65)(98+65) = 5.5 *s
=> 33*163 = 5.5 × s
=> 5379 = 5.5 ×s
=> s = 5379/5.5
=> s = 978m
Hence, the distance covered by the body is 978 metres.
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Answers & Comments
Answer:
Okey then bye
sayonara
I have to sleep
According to the Question
It is given that
We have to calculate the distance covered by body.
we will use here kinematics equation of motion.
Where v is the final velocity
a is the acceleration
u is the initial velocity
v is the final velocity
s is the displacement of the body
Substitute the value we get
=> 98² = 65²+ 2*2.75*s
=> 98² - 65² = 2*2.75*s
=> (98-65)(98+65) = 5.5 *s
=> 33*163 = 5.5 × s
=> 5379 = 5.5 ×s
=> s = 5379/5.5
=> s = 978m
Hence, the distance covered by the body is 978 metres.