Given, a = 4 m/s², u = 0, t = 10 s.

We know, from the second eq. of motion,

s = ut + (1/2)at²

or, s = 0 + (1/2)4*10 m

Therefore, s = 20 m. (Ans)

We know, from the first eq. of motion,

v = u + at

or, v = 0 + 4*10 m/s

Therefore, v = 40 m/s (ans)

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Answer:

40 velocity and 200 m distance I had answer