A wooden block of mass 6 kg is pulled across a rough surface by a 54 N force against a friction force F. The acceleration of the block is 6m/s^2 then value of the friction force F is....?
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Given,. friction=F
m=6kg
force=54Newton
acceleration=6m/s^2
As friction gives retardation to the force,so total acceleration
=(6m/s^2+F)
force =m❌(a+F)
54 = 6❌(6+F)
6+F= 54/6
= 9
retardation=9-6 m/s^2
=3m/s^2.
So ,retardation= 3m/s^2.
F1= m❌a
=6❌6
=36 netwon
But,force =54 N
So, frictional force=54-36
=18 N.