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3 Answers



Aunam Purkait, knows Hindi

Answered July 23, 2019

a=(v-u) /t

where ,

a= acceleration

v=final velocity

u=initial velocity

t=time

So, the acceleration is (8–2)/(3–1)=2m/s^2

Now,

s= ut+1/2at^2

=(0*4+1/2*2*4^2)m [as the particle started from rest]

=(0+16)m

=16m

For the 1st second displacement was 1/2*2*1^2=1m

Now,

average velocity

=total displacement /total time

=(16–1/4–1)m/s

=5m/s

2 nd method

Area of v-t curve =displacement

So, the displacement from t=1 to t=4sec is the red

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