Answer:
Therefore the final velocity of stone just before touching the ground will be 19.6 m/s.
Explanation:
initial velocity (u) = 0 m/s
Height (h) = 19.6 m
acceleration due to gravity (g) = 9.8 m/s^2
Let the final velocity just before touching the ground be v
We know, v^2 = u^2 + 2gh
or, v^2 = 0 + 2 × 9.8 × 19.6
or, v^2 = 19.6 × 19.6
or, v = 19.6
Thus the velocity of stone just before hitting the ground will be 19.6 metres per second .
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Verified answer
Answer:
Therefore the final velocity of stone just before touching the ground will be 19.6 m/s.
Explanation:
initial velocity (u) = 0 m/s
Height (h) = 19.6 m
acceleration due to gravity (g) = 9.8 m/s^2
Let the final velocity just before touching the ground be v
We know, v^2 = u^2 + 2gh
or, v^2 = 0 + 2 × 9.8 × 19.6
or, v^2 = 19.6 × 19.6
or, v = 19.6
Thus the velocity of stone just before hitting the ground will be 19.6 metres per second .