Answer:
[tex]\huge\red{Anwer}[/tex]
Velocity half second before maximum height
=
Velocity half second after maximum height (Return journey)
For downward journey :
Initial velocity
u=
0 m/s
We have
g=
9.8 m/s
2
Time
t=
1
s
Thus velocity after half second
v=
u+
gt
0+
9.8×
4.9m/s .
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Verified answer
Answer:
[tex]\huge\red{Anwer}[/tex]
Velocity half second before maximum height
=
Velocity half second after maximum height (Return journey)
For downward journey :
Initial velocity
u=
0 m/s
We have
g=
9.8 m/s
2
Time
t=
2
1
s
Thus velocity after half second
v=
u+
gt
v=
0+
9.8×
2
1
=
4.9m/s .
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