ANSWER:

1. 1. Final velocity ,v = 25m/s
2. Time, t = 20s
3. From, v = u + at
4. Acceleration, a = ?
5. a = (v — u)/t = (25 — 0)m/s/20s = 1.25m/s²
6. Acceleration = 1.25m/s²
7. Force = mass x acceleration
8. Force = 1500 x 1.25 = 1875N
9. - WHAT IS THE ACCELERATION
10. ANSWER: Rate of change of velocity
11. - WHAT FORCE IS ACTING ON IT
12. ANSWER: The point where the force is acting on an object is called the point of application of the force. The force which opposes the relative motion between the surfaces of two objects in contact and acts along the surfaces is called the force of friction.

        2. What force must act on 75.0kg mass to give it an acceleration of      1.2m/s2?

        ANSWER: 90.00N      

       75.0TIMES 1.2 FORCE IS TIMES MASS IS DIVIDE ACCELERATION IS DIVIDE