s2. 1. What is its velocity after 3s? 2. What is the distance covered after 3s? ...

Questions

CYPHERSYDNEY @CYPHERSYDNEY

October 2022 1 3 Report

A body that starts from rest moves to the right with an acceleration of 4 m/s2.

1. What is its velocity after 3s?
2. What is the distance covered after 3s? 3. What is the velocity of the body after it has travelled 20 m?

Answers & Comments

FierceFirefliee

initial velocity=u=0m/s
Acceleration=a=4m/s^2

Solution:-1

Time=t=3s
Final velocity=v=?

According to 1st equation of kinematics

$\boxed{\sf v=u+at}$

$\\ \sf\longmapsto v=0+4(3)$

$\\ \sf\longmapsto v=12m/s$

Solution:-2

Distance=s=?

According to second equation of kinematics

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=0(3)+\dfrac{1}{2}\times 4\times 3^2$

$\\ \sf\longmapsto s=2+9$

$\\ \sf\longmapsto s=11m$

Solution:-3

initial velcity=u=12m/s
Distance=s=20m
Final velocity=v

According to third equation of kinematics

$\boxed{\sf v^2-u^2=2as}$

$\\ \sf\longmapsto v^2-(12)^2=2(20)(4)$

$\\ \sf\longmapsto v^2-144=160$

$\\ \sf\longmapsto v^2=160+144$

$\\ \sf\longmapsto v^2=304$

$\\ \sf\longmapsto v=\sqrt{304}$

$\\ \sf\longmapsto v=17.3m/s$

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