hi ....

I'm from Kerala

Maximum height

Let maximum height be h. At maximum height, final velocity = 0

v'² - v² = -2gh' (-ve term as g acts downward)

0 - v² = -2gh'

v² = 2gh'

h' = h/2

v = \sqrt{2gh'}v=

2gh

′

19.6 = \sqrt{9.8h}19.6=

9.8h

19.6² = 9.8h

h = 39.2m

Velocity after 1s of throwing:

Initial speed, u = √(2gh)

h = maximum height

u = 19.6√2

Velocity after 1s,

v'' - u = -gt (-ve term as g acts downward)

v'' = 9.8 (2√2 - 1)

Acceleration:

Acceleration at all points is g = 9.8