Starting with a constant velocity of 50 km/h, a car accelerates for 32 seconds at an acceleration of 0.5 m/s². What is the velocity of the car at the end of the car at the of the period of 32 seconds of acceleration? Answer with solution.
To find the velocity of the car at the end of the period of 32 seconds of acceleration, we need to use the formula for average velocity during acceleration, which is given by:
v_f = v_i + at
where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time.
Given:
v_i = 50 km/h = 50 x 1000/3600 m/s = 13.89 m/s
a = 0.5 m/s²
t = 32 s
We can now substitute these values into the formula:
v_f = v_i + at
v_f = 13.89 m/s + 0.5 m/s² x 32 s
v_f = 13.89 m/s + 16 m/s
v_f = 29.89 m/s
So, at the end of 32 seconds of acceleration, the velocity of the car is 29.89 m/s.
Answers & Comments
Answer:
To find the velocity of the car at the end of the period of 32 seconds of acceleration, we need to use the formula for average velocity during acceleration, which is given by:
v_f = v_i + at
where v_f is the final velocity, v_i is the initial velocity, a is the acceleration, and t is the time.
Given:
v_i = 50 km/h = 50 x 1000/3600 m/s = 13.89 m/s
a = 0.5 m/s²
t = 32 s
We can now substitute these values into the formula:
v_f = v_i + at
v_f = 13.89 m/s + 0.5 m/s² x 32 s
v_f = 13.89 m/s + 16 m/s
v_f = 29.89 m/s
So, at the end of 32 seconds of acceleration, the velocity of the car is 29.89 m/s.