s: Use two integers and an operation to represent each situation.
1. A loss of 20 and a gain of 15.
2. A gain of 15, then a loss of twenty.
3. A gain of 20 and a gain of 35.
4. A loss of 19 and another loss of 30.
5. A raise of 15° and 10º fall in temperature
6. An altitude of 30,000 feet and another height of 15,000 feet
7. A loss of 15.000 feet and another loss of 12,000 feet.
8. A depth of 60 feet and a resting stop at 15 feet below the surface of
the water.
9. A depth of 15 feet and then another descent of 20 feet below the
surface of the water.
10. The hikers climbed to 1500 feet and then hiked another 1000 feet.
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1. A loss of 20 and a gain of 15.
2. A gain of 15, then a loss of twenty.
3. A gain of 20 and a gain of 35.
4. A loss of 19 and another loss of 30.
5. A raise of 15° and 10º fall in temperature
6. An altitude of 30,000 feet and another height of 15,000 feet
7. A loss of 15.000 feet and another loss of 12,000 feet.
8. A depth of 60 feet and a resting stop at 15 feet below the surface of
the water.
9. A depth of 15 feet and then another descent of 20 feet below the
surface of the water.
10. The hikers climbed to 1500 feet and then hiked another 1000 feet.
PA HELP NAMAN PO WITH SOLUTIONS PO FOLLOW KITA PLEASE
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In the given problem, apply your knowledge in algebra and basic mathematics specially in simplifying integer.
1. A loss of 20 and a gain of 15.
→ -20 + 15
2. A gain of 15, then a loss of twenty.
→ 15 - 20
3. A gain of 20 and a gain of 35.
→ 20 + 35
4. A loss of 19 and another loss of 30.
→ (-19) + (-30)
5. A raise of 15° and 10° fall in temperature
→ 15 + (-10)
6. An altitude of 30,000 feet and another height of 15,000 feet
→ 30 000 + 15 000
7. A loss of 15,000 feet and another loss of 12,000 feet.
→ (-15 000) + (-12 000)
8. A depth of 60 feet and a resting stop at 15 feet below the surface of the water.
→ (-60) + 15
9. A depth of 15 feet and then another descent of 20 feet below the surface of the water.
→ (-15) - 20
10. The hikers climbed to 1500 feet and then hiked another 1000 feet.
→ 1500 + 1000
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