a 7.0kg water melon is pushed across the table. if the acceleration of the water melon us 2.2m/s to the left,what is the external force exerted on the water melon
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Answer:
15.4 N
Explanation:
Given:
mass — 7.0 kg
acceleration — 2.2 m/s²
Formula: Force = mass×acc [F = ma]
F = (7.0 kg)(2.2m/s²)
F = 15.4 kg•m/s²
F = 15.4 Newtons
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