Explain briefly the procedure used to get the equation of the quadratic function given its zero/s, table of values, and graph. PASAGOT PO PLSS KAILANGAN KO NGAYON
Since the equation uses x2 you know this has to be a parabola. The vertex of the parabola can be found by using the two values given to you in the equation given. To find the x value of the vertex, you would find at what value would whatever you are squaring be 0, so x-3=0. This value is 3, so the x value is 3. To find the y value, you would use the c value, in this case -1. So, the vertex is (3,-1). To find the points where it crosses the x axis, you would find the x value where y=0. So, 0=2(x-3)2-1. From solving this formula you would get the values of 2.293,0 and 3.707,0. This is how you would graph the parabola.
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Answer:
Since the equation uses x2 you know this has to be a parabola. The vertex of the parabola can be found by using the two values given to you in the equation given. To find the x value of the vertex, you would find at what value would whatever you are squaring be 0, so x-3=0. This value is 3, so the x value is 3. To find the y value, you would use the c value, in this case -1. So, the vertex is (3,-1). To find the points where it crosses the x axis, you would find the x value where y=0. So, 0=2(x-3)2-1. From solving this formula you would get the values of 2.293,0 and 3.707,0. This is how you would graph the parabola.