Given:
Initial velocity, u = 15 m/s
Final velocity, v = 0 m/s
Time taken, t = 15 s
We can use the following kinematic equation to calculate the acceleration:
v = u + at
where
a = (v - u) / t
Substituting the given values, we get:
a = (0 - 15) / 15
a = -1 m/s^2
Therefore, the acceleration of the car is -1 m/s^2 (or 1 m/s^2 in the opposite direction of the car's motion).
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Answers & Comments
Given:
Initial velocity, u = 15 m/s
Final velocity, v = 0 m/s
Time taken, t = 15 s
We can use the following kinematic equation to calculate the acceleration:
v = u + at
where
a = (v - u) / t
Substituting the given values, we get:
a = (0 - 15) / 15
a = -1 m/s^2
Therefore, the acceleration of the car is -1 m/s^2 (or 1 m/s^2 in the opposite direction of the car's motion).