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sriram231
@sriram231
August 2021
2
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wooden slab starting from rest slides down an inclined plane of length 10 M with an acceleration of 5 m/s square what would be its speed at the bottom of the inclined plane
Answers & Comments
abhi5251
Answer is 10m/sec
we use the third equation of Newton
3 votes
Thanks 7
pavamuruganpbcfes
Wooden slab starts sliding down from rest
So that intial velocity u= 0
The length of the inclined plane is 10m
So s=10
It's acceleration is 5m/s²
So a=5m/S2
We need to find the final velocity i.e v
Using the equation of motion
V²-U²=2as
v²-0² = 2*5*10
v² =100
v=√100
so v is 10
This final velocity of the wooden slab is 10m/s.
Hope this helps you friend
Thanks ✌️ ✌️
6 votes
Thanks 8
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Answers & Comments
we use the third equation of Newton
So that intial velocity u= 0
The length of the inclined plane is 10m
So s=10
It's acceleration is 5m/s²
So a=5m/S2
We need to find the final velocity i.e v
Using the equation of motion
V²-U²=2as
v²-0² = 2*5*10
v² =100
v=√100
so v is 10
This final velocity of the wooden slab is 10m/s.
Hope this helps you friend
Thanks ✌️ ✌️