Two car starts of race with velocity of 2m/s and 4m/s travel in straight line with uniform acceleration 2m/s and 1m/s respectively. What is the length of the path if they reach the final point at the same point .
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Explanation:
Let the two cars be car
Let the two cars be car A
Let the two cars be car A and car
Let the two cars be car A and car B
Let the two cars be car A and car B.
Let the two cars be car A and car B.For car
A
:s1=ut+12at2⇒s
:s1=ut+12at2⇒s=4t+1×1×t2
(using second equation of motion)
(using second equation of motion)For car
(using second equation of motion)For car B
(using second equation of motion)For car B:
s2=ut+12at2⇒s2=2t+12×2×t2
(using second equation of motion)
On equating the distance,
s1=s2
s1=s2⇒4t+12×1×t2=2t+12×2×t2⇒2t=t22
⇒t=4 s
⇒t=4 sPutting the value in any one of the equations, we get
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Answer:
Let the two cars be car
Let the two cars be car A
Let the two cars be car A and car
Let the two cars be car A and car B
Let the two cars be car A and car B.
Let the two cars be car A and car B.For car
A
:s1=ut+12at2⇒s
:s1=ut+12at2⇒s=4t+1×1×t2
(using second equation of motion)
(using second equation of motion)For car
(using second equation of motion)For car B
(using second equation of motion)For car B:
s2=ut+12at2⇒s2=2t+12×2×t2
(using second equation of motion)
On equating the distance,
s1=s2
s1=s2⇒4t+12×1×t2=2t+12×2×t2⇒2t=t22
⇒t=4 s
⇒t=4 sPutting the value in any one of the equations, we get