acend Problem: The 0.17 kg cue ball hit the "8 ball" at rest". The cue ball and the 8 ball are travelling at 0.2 and 0.4 m/s respectively after the impact. Find the cue ball's velocity prior to collision given that the two pool balls have the same mass.
Add an Answer
More Questions From This User See All
Answers & Comments
We can use the law of conservation of momentum to solve this problem:
The total momentum before the collision is equal to the total momentum after the collision.
Let v be the velocity of the cue ball before the collision. The momentum before the collision is:
p1 = m1v
where m1 is the mass of the cue ball.
The momentum after the collision is:
p2 = m1v1 + m2v2
where m2 is the mass of the 8 ball, v1 is the velocity of the cue ball after the collision, and v2 is the velocity of the 8 ball after the collision.
Since the 8 ball is at rest before the collision, its initial momentum is zero:
p2 = m1v1
Using the law of conservation of momentum, we have:
p1 = p2
m1v = m1v1
v = v1
Therefore, the velocity of the cue ball prior to the collision is 0.2 m/s.