1. A pellet gun shoots a 30.0 g pellet at a speed of 200 m/s over a 50 ms interval. Find the
impulse.
Given: m=30.0g =0.03kg
impulse.
Given: m=30.0g =0.03kg
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Answer:
∆t = 50 ms = 0.05 s
Explanation:
v1 = 0 m/s
v2 = 200 m/s
∆t = 50 ms = 0.05 s
Solution: J = ∆p
F∆t = m∆v
= 0.03 Kg (200 m/s)
= 6.0 Ns