1)A little girl throws her ball horizontally out of the window with a velocity of 30m/s if the Window is 3m above the level ground, how far will the ball travel before it hits the ground? 2) A golf ball was hit and projected at an angle of G0 with the horizontal. If the initial velocity of the ball was 50m/s (neglect air friction), calculate the a) time the golf ball was in the air b) horizontal distance the ball traveled c) Maximum height the ball reached
Answers & Comments
Answer:
1.)The time of flight of the jack stone ball is calculated by using the formula of h = 1/2 gt^2 where h = 10 m, g = 9.8 m/s^2 and t is the time of flight.
It is equal to the square root of the quotient of the height h and one-half of g.
Solving for the time of flight
time of flight = square root (height / 4.9 m/s^2)
time of flight = square root (10 m / 4.9 m/s^2)
time of flight = square root (2.04 s^2)
time of flight = 1.43 s
The toy will hit the ground 1.43 seconds after being thrown horizontally.
2.)a). Time the golf ball was in the air = 8.66 seconds
b). Monzontal distance the ball. travel 216.5 m
c) maximum height the bull. reached = 93.75 m
Explanation: