Answer:

To find the force applied by the player to stop the ball, we can use Newton's second law of motion, which states that force (F) is equal to the rate of change of momentum (Δp) over time (Δt).

The momentum of an object is given by the product of its mass (m) and velocity (v), so we can calculate the initial momentum (p1) of the ball as:

p1 = m * v

Substituting the given values:

m = 70 g = 0.07 kg (converting grams to kilograms)

v = 0.5 m/s

p1 = 0.07 kg * 0.5 m/s

p1 = 0.035 kg·m/s

Now, the final momentum (p2) of the ball is zero since it comes to a stop. Therefore, the change in momentum (Δp) is given by:

Δp = p2 - p1

Δp = 0 - 0.035 kg·m/s

Δp = -0.035 kg·m/s

The time taken to stop the ball is given as Δt = 0.5 s.

Now, we can calculate the force (F) applied by the player using Newton's second law:

F = Δp / Δt

Substituting the values:

F = (-0.035 kg·m/s) / (0.5 s)

F = -0.07 N

The negative sign indicates that the force is in the opposite direction to the initial motion of the ball, representing the deceleration. Therefore, the force applied by the player to stop the ball is 0.07 N in magnitude.

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