A particle is moving along a circular path in
Xy-plane. When it crosses X-axis, it has an
acceleration along the path of 1.5 m/s2, and is
moving with a speed of 10m/s in negative
y - direction. The total acceleration is
Xy-plane. When it crosses X-axis, it has an
acceleration along the path of 1.5 m/s2, and is
moving with a speed of 10m/s in negative
y - direction. The total acceleration is
Answers & Comments
Answer:
hii!
here is ur answer
tangential acceleration = 1.5(given)
centripetal acceleration =v×v/r
here v is velocity and r is radius
by substituting v=10 and r=2
we get centripetal acceleration
= 10×10/2
= 50
the object is moving towards negetive y axis ( given) and there fore it is moving towards negetive x axis ( refer diagram)
so the answer is
= -50i -1.5j m/s
hope you understand
Answer:
Here’s u'r answer mate, hope this is OK and helps you and please mark me as brainliest