Michael Schumacher accelerates his race car uniformly from 18.2 m/s to 48.2 m/s in 2.45 s. Determine the magnitude of the acceleration of his car and the distance traveled.
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Answer:
GIVEN:Vi=18.2m/s ;Vf=48.2m/s ;T=2.45s
FIND: a.acceleration of his car
b.distance it had travelled
SOLUTION:
A: a= Vf—Vi
T
48.2-18.2
2.45
= 30
2.45
=4.99 Acceleration of his car
B: a= (Vf)(T)
= 48.2* 2.45= 118.09 Distance it had travelled
I HOPE ITS CORRECT :)
:)
Answer:
19.67m
19.67m is the distance traveled