Answer:

We know that the centrifugal force is the one that balanced the tension in the string. Then the stone is held spinning at a particular radius.

Given:

• m = 0.2 kg
• v = 12 m/s
• r = 0.5 m

Now, the centripetal force is given by the formula:

[tex]\to \sf F_c = \dfrac{mv^2 }{r}[/tex]

Where:

• m is mass
• r is radius
• v is the velocity

Now, we have:

[tex]\to \sf F_c = T[/tex]

[tex]\to \sf T = \dfrac{mv^2 }{r}[/tex]

[tex]\to \sf T = \dfrac{(0.2)(12)^2 }{0.5}[/tex]

[tex]\to \sf T = 57.6 \: N[/tex]

Therefore, the tension experienced by the string is 57.6 Newtons.