An ambulance is currently traveling at 15m/s and is accelerating with a constant acceleration of 5 m/s2. The ambulance is attempting to pass a car which is moving at a constant velocity of 30m/s. How far must the ambulance travel until it matches the car's velocity?

Answer:

B. 67.5 m

Explanation:

Given:

Initial velocity, u₁ = 15 m/s

Terminal velocity, u₂ = 30 m/s

Acceleration, a = 5 m/s²

Solution:

First, we calculate the amount of time needed to move at 30 m/s. We utilize the equation u2 = u1 + at, where t is the needed amount of time.

30 = 15 + 5t

5t = 15

t = 3s

The average velocity is now determined. If v represents the average speed, then

v = (u₁ + u₂)/2

v = (15 + 30)/2 m/s

v = 45/2 m/s

v = 22.5 m/s

The distance the ambulance went to match the speed of the automobile must now be calculated. To calculate the needed distance to be traveled, we utilize the formula s = vt.

s = 22.5 × 3 m

s = 67.5 m

In order to equal the car's speed, the ambulance must go 67.5 meters.

Reymark R. Bumatay

Bayambang National High School

Answer:

The correct answer is letter B.