Answer:
it takes 5 seconds for 15 m.
and 5m in first case.
Let Distance=D; Speed= S and Time=T
In this case, Time T is the same.
Distance = Speed x Time or D= SxT
In the first case, D = 1 xT or D =T ——->(1)
In the second case, D + 15 = 3 xT or 3 T ——->(2)
Using value of D as per (1) in (2),
T +15 = 3 T or 2T =15 or T=15/2= 7.5 seconds
As D=S x T, Distance covered in first case = 1m/second x 7.5 second= 7.5 meters
(Also, Distance covered in 2nd case = 7.5 + 15 = 22.5 mteres)
Explanation:
i hope that this answer will be right
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Answers & Comments
Answer:
it takes 5 seconds for 15 m.
and 5m in first case.
Answer:
Let Distance=D; Speed= S and Time=T
In this case, Time T is the same.
Distance = Speed x Time or D= SxT
In the first case, D = 1 xT or D =T ——->(1)
In the second case, D + 15 = 3 xT or 3 T ——->(2)
Using value of D as per (1) in (2),
T +15 = 3 T or 2T =15 or T=15/2= 7.5 seconds
As D=S x T, Distance covered in first case = 1m/second x 7.5 second= 7.5 meters
(Also, Distance covered in 2nd case = 7.5 + 15 = 22.5 mteres)
Explanation:
i hope that this answer will be right