A bullet of mass 10 g moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900 g . What is the velocity acquired by the wood
Answers & Comments
NerdyPepper
M1u1 + m2u2 = (m1 + m2)v Since the first body combines with the second. 10x400= 910 v on solving: v= 400/91 = 4.4 m/s
Answers & Comments
Since the first body combines with the second.
10x400= 910 v
on solving:
v= 400/91
= 4.4 m/s