s² for 60 s until it finally lifts off the ground. Determine the distance traveled before takeoff. (vi = 0)

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March 2023 1 3 Report

An airplane accelerates down a runway at 5 m/s² for 60 s until it finally lifts off the ground. Determine the distance traveled before takeoff. (vi = 0)

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SecretaryYumi

Answer:

157.44 m

Explanation:

cheng8959 We can use the kinematic equation:

distance = (initial velocity)(time) + (1/2)(acceleration)(time^2)

Since the initial velocity is zero, the equation simplifies to:

distance = (1/2)(acceleration)(time^2)

Substituting the given values, we have:

distance = (1/2)(5 m/s²)(60 s)^2
distance = (1/2)(5 m/s²)(3600 s²)
distance = 9000 meters

Therefore, the airplane traveled 9000 meters, or 9 kilometers, before takeoff.

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