Brakes are applied so as to produce an acceleration of 4m/s². Find distance covered by the object if it stops in 10sec. please answer this question friends....
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-4=0-u/10
u=40m/s.
as we know that,
stopping distance=u^2/2a
=1600/-8
=-200m.
mark BRAINLIEST PLEASE
t=10 sec
v=0
s=?
a=(v-u)/t
-4=(0-u)/10
-40=-u
u = 40m/
2as=v^2-u^2
2×-4×s=0-40^2
-8×s=-1600
s=200m