m. Problem Solving. Solve the following problems below. Show your solution and follow the format provided. Given:Required:Solution:
1. A bus with a mass of 2900kg is travelling at a speed of 3.5m/s. What is its kinetic energy? K.E=Yamv2
2. Suppose a ball of mass 0.60 kg is hit with a force of 8.5 N. Its acceleration will be. Fuma
3. The body builder lifted the weights using 800N force. What is the mass of the weights if it accelerates at 0.5m/s?? fema
4. if the same 3.3 kg stone is lifted to 1.2 m above the table, but the table top is 1.0 m above the floor, what would be the potential energy of the book if the reference level were the floor? P. E=mgh
Pasagot po kaylangan ko tlga naubos points ko po jan
1. A bus with a mass of 2900kg is travelling at a speed of 3.5m/s. What is its kinetic energy? K.E=Yamv2
2. Suppose a ball of mass 0.60 kg is hit with a force of 8.5 N. Its acceleration will be. Fuma
3. The body builder lifted the weights using 800N force. What is the mass of the weights if it accelerates at 0.5m/s?? fema
4. if the same 3.3 kg stone is lifted to 1.2 m above the table, but the table top is 1.0 m above the floor, what would be the potential energy of the book if the reference level were the floor? P. E=mgh
Pasagot po kaylangan ko tlga naubos points ko po jan
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Answer:
Problem 1:
Given:
m = 10 kg
v = 20 m/s
Required:
KE
Solution:
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Problem 2:
Given:
m = 6 kg
h = 3 m
Required:
PE
Solution:
PE = mgh
PE = (6 kg)(9.8 m/s²)(3 m)
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Problem 3:
Given:
m = 2,000 kg
d = 10 m
t = 60 s
Required:
P
Solution:
Solving for F
F = weight = mg
F = (2,000 kg)(9.8 m/s²)
F = 19,600 N
Solving for W
W = Fd
W = (19,600 N)(10 m)
W = 196,000 J
Solving for P
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Problem 4:
Given:
T = 26°C
Required:
v
Solution:
v = 331 + 0.6T
v = 331 + 0.6(26)
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Problem 5:
Given:
T = 29°C
Required:
v
Solution:
v = 331 + 0.6T
v = 331 + 0.6(29)
ation: