Answer:
The initial velocity of the helicopter, u = -15 m/s (since it is moving west)
The acceleration of the helicopter, a = 7.0 m/s^2 (since it is accelerating east)
The time for which the acceleration occurs, t = 4.0 s
Using the formula, v = u + at
where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Substituting the values, we get:
v = (-15 m/s) + (7.0 m/s^2 x 4.0 s)
v = -15 m/s + 28 m/s
v = 13 m/s (towards east)
Therefore, the final velocity of the helicopter is 13 m/s towards the east.
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Answers & Comments
Answer:
The initial velocity of the helicopter, u = -15 m/s (since it is moving west)
The acceleration of the helicopter, a = 7.0 m/s^2 (since it is accelerating east)
The time for which the acceleration occurs, t = 4.0 s
Using the formula, v = u + at
where,
v = final velocity
u = initial velocity
a = acceleration
t = time
Substituting the values, we get:
v = (-15 m/s) + (7.0 m/s^2 x 4.0 s)
v = -15 m/s + 28 m/s
v = 13 m/s (towards east)
Therefore, the final velocity of the helicopter is 13 m/s towards the east.