Answer:
7 m/s
Explanation:
Given:
Initial Velocity u=13 m/s
Acceleration a= -2 m/s^2
Time taken t= 6 s
Distance Travelled s=ut+at^2/2
= 13(6) - 1/2 * 2*(6)^2
= 78 - 36
= 42 m
We know that,
Avg. speed = Distance travelled / Time taken
= 42/6
Avg.speed = 7 m/s
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Answers & Comments
velocity of object at 5s = 13 + (-2)5=13-10=3 m/s
final velocity(v) = 3 m/s
velocity of object at 6 s = 3 + (-2) = 1
initial veloctity(u) = 1 m/s
average velocity = u + v / 2
= 1 + 3 /2
= 4/2
=2
so average velocity of object at 6 seconds = 2 m/s
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Answer:
7 m/s
Explanation:
Given:
Initial Velocity u=13 m/s
Acceleration a= -2 m/s^2
Time taken t= 6 s
Distance Travelled s=ut+at^2/2
= 13(6) - 1/2 * 2*(6)^2
= 78 - 36
= 42 m
We know that,
Avg. speed = Distance travelled / Time taken
= 42/6
Avg.speed = 7 m/s