Question:
1. How do you describe the height reached by the projectile at different?
2.At what angle does it reach the highest? the lowest?
3.Does the projection angle affect the maximum height reached? Why do you say so?
4.How do you describe the range covered by the projectile at different projectile angles?
5.At what angle/s does it reach the farthest? the nearest?
6.What angles cover the same range? What do you call these angles?
7.Does the projection angle affect the range covered? Explain briefly.
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Answers & Comments
Answer:
1.if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest
2.The launch. speed is held constant;only the angle is changed.
3.As such, maximum height also depends on the angle of projection. Horizontal component, being component of velocity, depends on the angle of projection. It is only the acceleration of projectile, which is equal to acceleration due to gravity and is, therefore, independent of the angle of projection.
4.Higher launch angles have higher maximum height
5.A projectile, in other words, travels the farthest when it is launched at an angle of 45 degrees.
6. 45⁰-Angles that have the same measure (i.e. the same magnitude) are said to be equal or congruent.
7.No,This highest point increases as the angle increases. ... For instance, the range is the same for a 15° and a 75° angle. The range is also the same for a 30° and a 60° launch angle. As a final example, the range is the same for a 40° and a 50° launch angle.
Explanation:
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