To determine the time for the feather to fall to the surface of the moon, we can use the following kinematic equation:

d = 1/2 * g * t^2

Where d is the distance fallen, g is the acceleration due to gravity, and t is the time taken.

We know that the initial height of the feather is 1.40 meters, and the acceleration due to gravity on the moon is 1.67 m/s². We can assume that the initial velocity of the feather is zero.

Substituting these values into the equation, we get:

1.40 = 1/2 * 1.67 * t^2

Simplifying, we get:

t^2 = 1.40 / (1/2 * 1.67)

t^2 = 1.40 / (1/2 * 1.67)t^2 = 1.68

Taking the square root of both sides, we get:

t = 1.30 seconds

Therefore, it takes approximately 1.30 seconds for the feather to fall to the surface of the moon.