• Initial Velocity (u) = 60 m/s
• Final Velocity (v) = 0 m/s
• Time (t) = 3 seconds
• Acceleration produced (a)
We know that, acceleration is measure of the change in velocity of an object per unit time.
★ Acceleration = Final Velocity - Initial Velocity/Time taken
→ a =
→ a = - 20 m/s²
Acceleration produced is - 20 m/s².
The negative sign of acceleration means that it is retardation. So, we can also say that the bus has a retardation of + 20m/s.
◉ Initial velocity of bus, u = 60 m/s
◉ Final velocity of bus, v = 0 m/s [∵ The bus comes to rest]
◉ Time taken by the bus to come to rest, t = 3s
◉ Acceleration produced by the bus after applying the brakes.
We need to find the acceleration, So
By the first equation of motion,
⇒ v = u + at
Substituting values,
⇒ 0 = 60 + a×3
⇒ -60 = 3a
⇒ a = -20 m/s²
Hence, The acceleration produced was -20 m/s²
Some Information :-
◉ The negative acceleration is also known as Deceleration or Retardation.
◉ Other equations of motion:
Where,
◉ Acceleration is the rate of change of velocity per unit time, It is a vector quantity, Meaning It has both magnitude and direction.
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Answers & Comments
Verified answer
Given :
• Initial Velocity (u) = 60 m/s
• Final Velocity (v) = 0 m/s
• Time (t) = 3 seconds
To Find :
• Acceleration produced (a)
Solution :
We know that, acceleration is measure of the change in velocity of an object per unit time.
★ Acceleration = Final Velocity - Initial Velocity/Time taken
→ a =![\sf\dfrac{0-60}{3} \sf\dfrac{0-60}{3}](https://tex.z-dn.net/?f=%5Csf%5Cdfrac%7B0-60%7D%7B3%7D)
→ a =![\sf\cancel\dfrac{-60}{3} \sf\cancel\dfrac{-60}{3}](https://tex.z-dn.net/?f=%5Csf%5Ccancel%5Cdfrac%7B-60%7D%7B3%7D)
→ a = - 20 m/s²
The negative sign of acceleration means that it is retardation. So, we can also say that the bus has a retardation of + 20m/s.
Verified answer
Given :-
◉ Initial velocity of bus, u = 60 m/s
◉ Final velocity of bus, v = 0 m/s [∵ The bus comes to rest]
◉ Time taken by the bus to come to rest, t = 3s
To Find :-
◉ Acceleration produced by the bus after applying the brakes.
Solution :-
We need to find the acceleration, So
By the first equation of motion,
⇒ v = u + at
Substituting values,
⇒ 0 = 60 + a×3
⇒ -60 = 3a
⇒ a = -20 m/s²
Hence, The acceleration produced was -20 m/s²
Some Information :-
◉ The negative acceleration is also known as Deceleration or Retardation.
◉ Other equations of motion:
Where,
◉ Acceleration is the rate of change of velocity per unit time, It is a vector quantity, Meaning It has both magnitude and direction.