Answer:

Step 1: List the given values

Given, the initial velocity of the bus, v_{i} = 18km / h * r

We know that 1km / h * r = 5/18 * m / s 18km / h * r = (5/18 * 18) * m / s

= 5m / s

The final velocity of the bus v_{f} = 0 since the

bus comes to rest

The time taken t = 2 s Step 2: Calculate the retardation We know that acceleration,

a = (v_{f} - v_{i})/t = (0 - 5)/2.5 = - 2m / (s ^ 2)

We know that retardation is the negative of acceleration.

a_{r} = - a

a_{r} = 2m / (s ^ 2)

Hence, the required retardation is 2m / (s ^ 2)

[tex] \huge\mathfrak{★answer★}[/tex]

We have to find the distance

travelled and final velocity of

the body. We have the following

information given,

Initial velocity, (u) = 5 m/s

Acceleration, (a) = 0.2 m/s²

Time taken, (t) = 10 s

So, we can find the final

velocity using the relation,

V = u + at

So, final velocity,

v = 5+ (0.2) (10)

= 7 m/s

We can calculate the distance travelled by using the

2nd equation of motion,

[tex] \sf \red{s = ut + \frac{1}{2} at²}[/tex]

Put the values in above

equation to find the distance

travelled by the motorcycle,

[tex] \sf \pink{(s) = 5(10) + \frac{1}{2} (0.2) \: (10)²}[/tex]

= (50 + 10) m

= 60 m