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Answer:

Explanation:

To calculate the distance the car will travel before coming to a complete stop, we can use the kinematic equation that relates initial velocity, final velocity, acceleration (or deceleration), and distance:

\[v_f^2 = v_i^2 + 2a d\]

Where:

- \(v_f\) is the final velocity (0 m/s, as the car comes to a complete stop).

- \(v_i\) is the initial velocity (30 m/s).

- \(a\) is the acceleration (deceleration in this case, -4 m/s²).

- \(d\) is the distance we want to find.

Plugging in the given values:

\[0^2 = (30^2) + 2(-4)d\]

Simplifying:

\[0 = 900 - 8d\]

Now, solve for \(d\):

\[8d = 900\]

\[d = \frac{900}{8}\]

\[d = 112.5\]

So, the car will travel a distance of 112.5 meters before coming to a complete stop.

Explanation:

You can use the kinematic equation to calculate the distance traveled:

\[v_f^2 = v_i^2 + 2a d\]

Where:

- \(v_f\) is the final velocity (0 m/s, since the car comes to a stop)

- \(v_i\) is the initial velocity (30 m/s)

- \(a\) is the acceleration (-4 m/s², since the car is decelerating)

- \(d\) is the distance traveled

Plugging in the values:

\[0^2 = 30^2 + 2 \cdot (-4) \cdot d\]

Solving for \(d\):

\[d = \frac{30^2}{2 \cdot 4} = 225\]

So, the car will travel 225 meters before coming to a complete stop.