1 .)What is the kinetic energy of an airplane with a total mass of 50,000kg that is
moving at a velocity of 250m/s? Answer: __________
2.) A 50 kg gorilla is sitting on the limb of a tree 4 meters above the ground. The
gorilla jumps down from the tree limb to the ground. Use the Conservation of
Mechanical Energy to find the velocity of the gorilla just before hitting the
ground. Answer: __________
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1 .)What is the kinetic energy of an airplane with a total mass of 50,000kg that is moving at a velocity of 250m/s? Answer: __________
K.E. = 1/2mv²
= 1/2 × 50000 kg × (250 m/s)²
= 25000 kg × 62500 m²/s²
= 1,562,500,000 J
2.) A 50 kg gorilla is sitting on the limb of a tree 4 meters above the ground. The gorilla jumps down from the tree limb to the ground. Use the Conservation of Mechanical Energy to find the velocity of the gorilla just before hitting the ground.
1960 J = 1/2mv²
v² = 1960 J / 1/2m
v = √ 1960 J / 1/2 ( 50 kg )
=√ 1960 J / 25 kg
= √ 78.4 m²/s²
= 8.85 m/s ( before it hits the ground )
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