A body 'A' is projected upwards with a velocity of 98 m/s and a second body 'B' is projected upwards with the same initial velocity but after 4 seconds. Both the bodies will meet after
a) 6 seconds
b) 8 seconds
c) 10 seconds
d) 12 seconds
Please answer ASAP with explanation
a) 6 seconds
b) 8 seconds
c) 10 seconds
d) 12 seconds
Please answer ASAP with explanation
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Answer:
Both the bodies will meet after 12 seconds.
Solution:
As the initial velocity at which the bodies A and B projected are same and also the position pf meeting will also be same so
The height covered by the projecting body is
The time taken to reach the point H for object A is t
The time taken to reach the point H for object B is (t-4) as the object B is thrown after 4s of throwing A. So,
As u = 98 m/s , the above equation will become as
Thus, it will take 12 s by object B to join object A.
Explanation:
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