When a particle is travelling uniformly in a circle at a constant speed, the velocity vector's direction changes, causing an acceleration, but the particle's acceleration itself doesn't change. The formula is a = v/t= (vf-vi)/. (tf - ti). After subtracting the initial speed from the final velocity, multiply the result by the time interval. Your average acceleration throughout that period is the end result.
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Answer:
When a particle is travelling uniformly in a circle at a constant speed, the velocity vector's direction changes, causing an acceleration, but the particle's acceleration itself doesn't change. The formula is a = v/t= (vf-vi)/. (tf - ti). After subtracting the initial speed from the final velocity, multiply the result by the time interval. Your average acceleration throughout that period is the end result.
initial speed (u)= 40m/s
final speed(v) =v
a = 4m/s²
t = 10sec
as we know:
v=u+at
v = 410+ 40
v = 40+ 40
v = 80m/s
Explanation:
Verified answer
Answer:
The body moves 200 m/s after 10 seconds.
Explanation:
Equation:
[tex]\boxed{ \bold{v_f = v_1 + at}}[/tex]
Given:
[tex]v_f[/tex] = ?
[tex]v_1[/tex] = 4 m/s
[tex]a[/tex] = 4 m/s²
[tex]t[/tex] = 10 s
Required:
final velocity of the body
Solution:
[tex]v_f = 4 m/s + (4 m/s)² ( 10 s) [/tex]
[tex]v_f = { \underline{ \underline{200 \: m/s}}}[/tex]
Therefore, the body moves 200 m/s after 10 seconds.
[tex] \: [/tex]
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