Define the decay constant of 14C, if its half-life is 5600 years.
explain
Select one:
A 3.9x10^3 1/s
B 1.24x10^(-4) 1/s
C 2.55×10^11 1/s
D 3.92×10^(-12) 1/s
explain
Select one:
A 3.9x10^3 1/s
B 1.24x10^(-4) 1/s
C 2.55×10^11 1/s
D 3.92×10^(-12) 1/s
Answers & Comments
Explanation:
The decay constant (λ) of a radioactive isotope is a measure of the rate at which the isotope decays. It is typically measured in inverse seconds (1/s). The half-life (T1/2) of a radioactive isotope is the amount of time it takes for half of the isotope to decay.
The relationship between the decay constant and the half-life is given by the formula:
λ = ln(2)/T1/2
Given that the half-life of 14C is 5600 years, we can calculate the decay constant as follows:
λ = ln(2)/5600 years
λ = ln(2)/5600* (1 year/31536000 s) = 1.24×10^(-4) 1/s
Therefore, the decay constant of 14C is B 1.24x10^(-4) 1/s
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