Answer:
The Power P = 100 W and Voltage V = 220 V. So, current I is I = P/V = 100/220 = 0.45 A. When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W. Hence, the power consumed when operated at 110 V is 50 W.
According to the Question
It is given that,
we have to calculate the voltage supply to which a rating 200 w bulb .
Here the energy consumed at the rate of 100J/s .
is power of bulb .
Means P' = 100 W
Firstly calculating the Current in 1st case
On substituting the value we get
↠ 200 = 220 × I
↠ I = 200/220
↠ I = 0.90 A or 10/11 A
here the current supply to bulb is constant .
Now, calculating the voltage in 2nd case
Let the voltage at 2nd case is V'
↠ 100 = V' × 10/11
↠ V' = 100×11/10
↠ V' = 110v
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Answers & Comments
Answer:
The Power P = 100 W and Voltage V = 220 V. So, current I is I = P/V = 100/220 = 0.45 A. When the supplied voltage is 110 V, the power consumed will be P=VI = 110 * 0.45 = 50 W. Hence, the power consumed when operated at 110 V is 50 W.
Verified answer
According to the Question
It is given that,
we have to calculate the voltage supply to which a rating 200 w bulb .
Here the energy consumed at the rate of 100J/s .
is power of bulb .
Means P' = 100 W
Firstly calculating the Current in 1st case
On substituting the value we get
↠ 200 = 220 × I
↠ I = 200/220
↠ I = 0.90 A or 10/11 A
here the current supply to bulb is constant .
Now, calculating the voltage in 2nd case
Let the voltage at 2nd case is V'
On substituting the value we get
↠ 100 = V' × 10/11
↠ V' = 100×11/10
↠ V' = 110v