A train 2km in the first 10 minutes, 10 km in the next 10 minutes,30 km in the next 10 minutes and 60 minutes in the next 10 minutes. What type of motion is exhibited by this train? Calculate its average speed in m/s
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Explanation:
average speed = total distance /total time
total distance =2+10+30+60=102 km=102000m
total time taken=10 +10+10 +10 =40min= 40*60=2400sec
av speed= 102000 /2400=1020/24
1020/24=5m/sec
as train is covering more distance as give time interval,speed of train is increasing in given time interval so it accelareting
Answer:
The motion is acceleration.
The avg. speed = (2+10+30+60)/40 = 102/40 =2.55km/min = 2.55 ×1000/60 =42.5m/s