1.a car travels at 9.0 km/hr find the acceleration of the car in 3 hours if it starts from rest.
2. As a bike comes to a stop if slow down from 20 m/s in 2.0 s . What is the acceleration of the bike?
3. if a car, with an initial velocity of 10 m/s accelerates at a rate of 50 m/s² for 3 s .What will its final velocity be?
4. an object is an accelerating at 4 m/s² how long will it take to change its speed from 8 m/s to 12 m/s?
Answers & Comments
The car's initial velocity is 0 km/hr since it starts from rest. We need to convert the velocity to m/s to calculate the acceleration.
9.0 km/hr = 2.5 m/s
Using the formula for acceleration:
a = (v - u) / t
where a is acceleration, v is final velocity, u is initial velocity, and t is time
a = (2.5 m/s - 0 m/s) / 3 hours
a = 0.83 m/s²
Therefore, the acceleration of the car is 0.83 m/s².
The bike's initial velocity is 20 m/s. We can use the same formula for acceleration:
a = (v - u) / t
where a is acceleration, v is final velocity, u is initial velocity, and t is time
a = (0 m/s - 20 m/s) / 2.0 s
a = -10 m/s² (note the negative sign indicates deceleration)
Therefore, the acceleration of the bike is -10 m/s².
The car's initial velocity is 10 m/s, acceleration is 50 m/s², and time is 3 seconds. We can use the formula for final velocity:
v = u + at
where v is final velocity, u is initial velocity, a is acceleration, and t is time
v = 10 m/s + (50 m/s²)(3 s)
v = 160 m/s
Therefore, the final velocity of the car is 160 m/s.
We can use the formula for acceleration to calculate the time it takes to change speed from 8 m/s to 12 m/s, assuming constant acceleration:
a = (v - u) / t
where a is acceleration, v is final velocity, u is initial velocity, and t is time
a = (12 m/s - 8 m/s) / t
a = 4 m/s²
Substituting the acceleration and initial velocity values into the formula:
t = (v - u) / a
t = (12 m/s - 8 m/s) / 4 m/s²
t = 1 s
Therefore, it will take 1 second for the object to change its speed from 8 m/s to 12 m/s.