A baseball infielder, mass 75.0 kg, jumps up with velocity 2.00 m/s and catches a 0.150-kg baseball moving horizontally at 50.0 m/s. Of the following, which is closest to the final momentum of the system, infielder and baseball?
a.
152 kgm/s
b.
150 kgm/s
c.
155 kgm/s
d.
158 kgm/s
Answers & Comments
If a baseball infielder with a mass of 75 kilograms jumps up with a velocity of 2 m/s and then catches a 0.150-kilogram baseball moving horizontally at 50 m/s, the closest value to the system's final momentum, infielder, and the baseball is 150 kg-m/s.
We can solve this by simply multiplying the distance by the mass of the object and getting the resultant value.
First, let us calculate the initial momentum for both directions (horizontal and vertical).
Solving for the momentum:
Horizontal momentum = 75 kg x 2m/s = 150 kg-m/s
Vertical momentum = 0.150 kg x 50 m/s = 7.5 kg-m/s
Now we have the horizontal and vertical values, we can now use the distance formula or Pythagorean theorem to solve for the final momentum.
R= [tex]\sqrt[]{150^{2} +7.5^{2} }[/tex] = 150.187383 kg-m/s
Thus, the closest value for the final or resultant momentum is 150 kg-m/s.
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