2. A soccer ball is kicked 35° above with an initial velocity of 23.0 m/s and reaches a maximum height of 1.27 m at 0.10 second. Determine the horizontal displacement

(range) of the ball.

V.- 23 m/s

sin 6-0.574 0

cos 0 = 0.819 t = 0.10 s Find:

Range (d,) = ?

Solution:

Equation:

d. - v. cos e t

d. (23 m/s) (0.819) (0.20 s)

d₂= 3.77 m

solve for t

t-2t

t = 2 (0.10 s)

t-0.20 s

Let us now do the activities below. Use a separate paper for your answer.

35⁰

60"

75°

stions: Write y

1. What is

2. At wha

3. Compe

Given:

4. At wh

Compat

sure:

ning​