Ruel has a rectangular plece of cardboard whose dimensions inches, what is its perimeter? are in the ratio 4:5. If the area of the cardboard is 720 square
Answers & Comments
elaifuentes11
Let's first use algebra to find the dimensions of the cardboard.
Let x be the common ratio of the dimensions. Then the length of the cardboard is 4x and the width is 5x.
The area of the cardboard is given as 720 square inches:
(4x) * (5x) = 720
20x^2 = 720
x^2 = 36
x = 6
So the length of the cardboard is 4x = 4 * 6 = 24 inches, and the width is 5x = 5 * 6 = 30 inches.
Now we can use the formula for the perimeter of a rectangle:
Perimeter = 2(length + width)
Perimeter = 2(24 + 30)
Perimeter = 2(54)
Perimeter = 108 inches
Therefore, the perimeter of the cardboard is 108 inches.
Answers & Comments
Let x be the common ratio of the dimensions. Then the length of the cardboard is 4x and the width is 5x.
The area of the cardboard is given as 720 square inches:
(4x) * (5x) = 720
20x^2 = 720
x^2 = 36
x = 6
So the length of the cardboard is 4x = 4 * 6 = 24 inches, and the width is 5x = 5 * 6 = 30 inches.
Now we can use the formula for the perimeter of a rectangle:
Perimeter = 2(length + width)
Perimeter = 2(24 + 30)
Perimeter = 2(54)
Perimeter = 108 inches
Therefore, the perimeter of the cardboard is 108 inches.