Question: Rewrite each quadratic equation in standard form. (3j+5)(2j-3)=0
Answer: 6j²+1j-15=0
Solution:
(3j+5)(2j-3)=0
6j²-9j+10j-15=0 (USING FOIL METHOD)
6j²+1j-15=0
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Question: Rewrite each quadratic equation in standard form. (3j+5)(2j-3)=0
Answer: 6j²+1j-15=0
Solution:
#USING "ax²+bx+c=0"
(3j+5)(2j-3)=0
6j²-9j+10j-15=0 (USING FOIL METHOD)
6j²+1j-15=0
Quadratic Term=6j²
Linear Term=1j
Constant Term=-15
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