A person invests a sum of $6580 at an 8% per annum rate of interest to obtain a total amount of $8685.6 including simple interest after a certain number of years. For how many years did he invest the amount to obtain the total amount? 5 years 4 years 6 years 3 years
Answers & Comments
ritampramanik75
Ans- 4years I = interest P = sum invested A = amount T = time R = rate of interest We know, I = (P×R×T)÷100 Therefore, I = (6580×8×T)÷100 = 526.4×T -----------------------(i) According to question, A = 8685.6 I = A - P = 8685.6 - 6580 =2105.6 -----------------------(ii) From equation (i) and (ii) we get, 526.4×T = 2105.6 T = 4 Hence, 4 years.
Answers & Comments
I = interest
P = sum invested
A = amount
T = time
R = rate of interest
We know,
I = (P×R×T)÷100
Therefore,
I = (6580×8×T)÷100
= 526.4×T -----------------------(i)
According to question,
A = 8685.6
I = A - P
= 8685.6 - 6580
=2105.6 -----------------------(ii)
From equation (i) and (ii) we get,
526.4×T = 2105.6
T = 4
Hence, 4 years.