Step 2: Draw a circle centered at A and radius AB. Let C, D be the intersection points of the circle (A,AB)(A,AB) and the X-axis line. The coordinates of C and D would be:
C(1−2√2,0);C(1−22,0);
D(1+2√2,0).D(1+22,0).
Step 3: Draw E(1,3)E(1,3) . The length of DE would be
Step 4: Draw a circle centered at A that has a radius of DE. Let F, G be the intersection points of the circle (A, DE) and the X-axis line. The coordinates of F and G would be:
F(1−9.5−−−√,0)F(1−9.5,0)
G(1+9.5−−−√,0)G(1+9.5,0)
Because the X-axis line is a number line, you have successfully represented the point 1+9.5−−−√1+9.5 on the number line.
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CRM
ya sure but if another person answers only I can mark u as brainliest
Answers & Comments
According to the Pythagoras theorem, the length of AB would be
AB=|1−1.5|2+|0−0.5|2−−−−−−−−−−−−−−−−−√=2√2.AB=|1−1.5|2+|0−0.5|2=22.
Step 2: Draw a circle centered at A and radius AB. Let C, D be the intersection points of the circle (A,AB)(A,AB) and the X-axis line. The coordinates of C and D would be:
C(1−2√2,0);C(1−22,0);
D(1+2√2,0).D(1+22,0).
Step 3: Draw E(1,3)E(1,3) . The length of DE would be
DE=|1−(1+2√2)|2+|0−3|2−−−−−−−−−−−−−−−−−−−−√=9.5−−−√DE=|1−(1+22)|2+|0−3|2=9.5
Step 4: Draw a circle centered at A that has a radius of DE. Let F, G be the intersection points of the circle (A, DE) and the X-axis line. The coordinates of F and G would be:
F(1−9.5−−−√,0)F(1−9.5,0)
G(1+9.5−−−√,0)G(1+9.5,0)
Because the X-axis line is a number line, you have successfully represented the point 1+9.5−−−√1+9.5 on the number line.