Renz Joseph saved Php10 on the first day, Php15 on the second day, Php20 on the third day and so on. If the pattern continues, how much will he save for one year?
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Answer:
Step-by-step explanation:
5,10,15,20,25,30 and so on
So this will be an AP
number of days in 1 year=365
A1=5,
d=5
An=A1+(n-1)d
A365=5+(365-1)5=5+364*5=5+1820=1825
SO
he will save for one year=1825